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Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan theta}{1+tan ^{2}theta}

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Click here:point_up_2:to get an answer to your question :writing_hand:prove rightarrow sin 90othetacos 90othetadfrac tan theta1tan 2theta
Click herešŸ‘†to get an answer to your question āœļø Prove rightarrow sin -90-o-theta-cos -90-o-theta-dfrac -tan theta-1-tan -2-theta-
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Prove that : tantheta+tan(90^(@)-theta)=sectheta*sec(90^(@)-theta)

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33 Prove that ( frac { cot ( 90 - theta ) } { tan theta } + frac { csc ( 90 - theta ) sin theta } { tan ( 90 - theta ) } ) ( = sec ^ { 2 } theta )

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Prove that ( : frac { cot left( 90 ^ { circ } - theta right) } { tan theta } + frac { csc left( 90 ^ { circ } - theta right) } { tan left( 90 ^ { circ } - theta right) } cdot sin theta = sec ^ { 2 } theta )

ą¤øą¤æą¤¦ą„ą¤§ ą¤•ą„€ą¤œą¤æą¤ (cos (90^(@)-A)sin (90^(@)-A))/(tan (90^(@)-A))=sin^(2)A.

Prove that : (i) `sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1`

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prove that cot(90-theta) ā€¢ sin(90-theta)/cos 90-theta) = 1ā€‹