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Click here👆to get an answer to your question ✍️ At 300 K- 36 g of glucose present in a litre of its solution has an osmotic pressure of 4-98 bar- If the osmotic pressure of the solution is 1-52 bars the same temperature- what would be its concentration-
As per the van-apos-t Hoff equation- the relationship between the osmotic pressure and the molar concentration is-xA0- -x3A0-CRT- Here- R is the ideal gas constant and T is absolute temperature-C1-36180 M-Note- Molar mass of glucose is 180 g-mol and molar concentration is the ratio of number of moles of glucose to the volume of solution in L- Number of moles is the ratio of mass to molar mass-x3A0-1-4-98 barC2- -x3A0-2-1-52-xA0- bar4-98-36180 RT -i-1-52-C2 RT -ii-Divide equation -ii- with equation -i-xA0-C236-xD7-180-1-524-98C2-0-061-xA0-MHence- second solution has concentration of 0-061-xA0-M
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At 300 K, 36 g of glucose present per litre in its solution has an osm
2.22At300 K,36 g of glucose present in a litre of its solution has an osm..
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At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98
At 300 K , 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars
At 300K, 36g of glucose present in a litre of its solution has an osmotic pressure of 4.98bar.
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