∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?
Fig. 15.12. In Fig. 15.30, A ABC is an isosceles triangle with AB
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height
Question 8 Δ ABC is isosceles with AB = AC =7.5 cm and BC =9 cm
In the figure, given below, ABC is an isosceles triangle with BC
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Delta ABC is isosceles with AB = AC = 7.5 m and BC = 9 cm The height A
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DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD
ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height
DeltaABC is isosceles with AB=AC. Line segment AD bisects angle A
