6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90..

6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150
Video solution 1: 6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150
Video solution 2: 6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2​ cos(90+60)=−sin60∘=−8​/2cos(180∘−30)=−cos30=−3​/2​ cos150

What is the value of sin150? - Quora

Show that : `(i) (1-sin60^(@))/(cos60^(@))=(tan60^(@)-1)/(tan60^(@)+1)` `(ii) (cos30^(@)+sin60^(@))/

SOLVED: -cos 30^∘=(√(3))/(2) -cos 60^∘=(1)/(2) -cos 90^∘=0 -cos 120^∘=(180^∘ -60^∘)=-cos 60^∘=-(1)/(2) -cos 180^∘=cos(180^∘-80^∘)=-cos 30^∘=(-√(3))/(2) -cos 180^∘=cos(180^∘-0^∘)=-cos 60^∘=-(1)/(2) -cos 210^∘=cos(180^∘+30^∘)=-30

Show that: 1-sin60/ cos60 = tan60 -1/tan60 +1 - Sarthaks eConnect

Find tan(60), cos(60), and sin(60) using the 30-60-90 Triangle Theorem.

6. sin150 Sin(90+60)​=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90..

Evaluate `, [sin 60^(@), cos60^(@)], [sin 30^(@), cos 30^(@)]

Evaluate: sin 60° cos30° + sin 30° cos 60°

Given that sin 60=√3/2 and cos 60=1/2 evaluate 1-sin60/1+cos 60? - Myschool

6 𝑐𝑜𝑠60−sin⁡30+sin^2 45+𝑐𝑜𝑠^2 45#shorts #sslcexam2022

Evaluate each of the followingsin 30∘ sin 90∘+2 cos 0∘tan 30∘tan 60∘